Respuesta :
Answer:
The answer to your question is TlC₂H₃O₂
Explanation:
Data
Tl = 0.463g
C = 0.0544 g
H = 0.00685 g
O = 0.0725 g
Process
1.- Convert the mass of each element to moles
Thalio
204.4g ---------------- 1 mol
0.463 g --------------- x
x = (0.463 x 1) / 204.4
x = 0.0023 moles
Carbon
12 g ------------------ 1 mol
0.0544 g ---------- x
x = (0.0544 x 1) / 12
x = 0.0045 moles
Hydrogen
1 g ------------------ 1 mol
0.00685 g -------- x
x = (0.00685 x 1) / 1
x = 0.00685 moles
Oxygen
16 g -------------- 1 mol
0.0725 g ---------- x
x = (0.0725 x 1) / 16
x = 0.0045 moles
2.- Divide the number of moles by the lowest number of moles
Thalio 0.0023 / 0.0023 = 1
Carbon 0.0045 / 0.0023 = 1.9 ≈ 2
Hydrogen 0.0069 / 0.0023 = 3
Oxygen 0.0045 / 0.0023 = 1.9 ≈ 2
3.- Write the empirical formula
TlC₂H₃O₂
Answer:
The empirical formula is C2H3O2Tl
Explanation:
Step 1: Data given
Mass of Tl = 0.463 grams
Mass of carbon = 0.0544 grams
Mass of hydrogen = 0.00685 grams
Mass of oxygen = 0.0725 grams
Molar mass of Tl = 204.38 g/mol
Molar mass of C = 12 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16 g/mol
Step 2: Calculate total mass of the compound
Total mass = 0.463 grams + 0.0544 grams + 0.00685 grams + 0.0725 grams = 0.59675 grams
Step 3: Calculate moles
Moles = mass / molar mass
Moles Tl = 0.463 grams / 204.38 g/mol = 0.00227 moles
Moles C = 0.0544 grams / 12.0 g/mol = 0.00453 moles
Moles H = 0.00685 grams / 1.01 g/mol = 0.00678 moles
Moles O = 0.0725 grams / 16 g/mol = 0.00453 moles
Step 4: Calculate mol ratio
We divide by the smallest number of moles
Tl = 0.00227/0.00227 = 1
C = 0.00453 / 0.00227 = 2
H = 0.00678/0.00227 = 3
O = 0.00453 / 0.00227 = 2
The empirical formula is C2H3O2Tl
