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Shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage. Determine the reading of the pressure gage, in lbf/in^2. (gage). The densities of the oil and mercury are 55 and 845, respectively, each in lb/ft^3. Let g=32.2ft/s^2.

Respuesta :

Answer:

[tex]P_2-P_1=27209h[/tex]

Explanation:

For pressure gage we can determine this by saying:

The closed tank with oil and air has a pressure of P₁ and the pressure of oil at a certain height in the U-tube on mercury is p₁gh₁. The pressure of mercury on the air in pressure gauge is p₂gh₂. The pressure of the gage is P₂.

[tex]P_1+p_1gh_1=p_2_gh_2+P_2[/tex]

We want to work out P₁-P₂: Heights aren't given so we can solve it in terms of height: assuming h₁=h₂=h

[tex]P_1-P_2=p_1gh_1-p_2gh_2=(55)\cdot{32.2}h-845\cdot{32.2}h[/tex]

[tex]P_2-P_1=27209h[/tex]

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