Answer:
Principle quantum number, n = 2
l = 0, 1
if l = 0 , m = 0
l = 1, m = -1, 0, +1
Total number of orbitals = 4
Principle quantum number, n = 3
l = 0, 1, 2
if l = 0 , m = 0
l = 1, m = -1, 0, +1
l = 2, m = -2, -1, 0, +1, +2
Total number of orbitals = 9
Explanation:
Principle quantum number, n = 2
L can take values from 0 to n-1 .
So, l = 0, 1
The values of m = -l to l
So, if l = 0 , m = 0
l = 1, m = -1, 0, +1
Total number of orbitals = 4 which are s orbital (l =0) and 3 p orbitals (l =1)
Principle quantum number, n = 3
L can take values from 0 to n-1 .
So, l = 0, 1, 2
The values of m = -l to l
So, if l = 0 , m = 0
l = 1, m = -1, 0, +1
l = 2, m = -2, -1, 0, +1, +2
Total number of orbitals = 9 which are s orbital (l =0) and 3 p orbitals (l =1) and 5 d orbitals (l = 2)
