Respuesta :
Answer: The mass of sulfur dioxide is 14.6 grams
Explanation:
To calculate the number of moles, we use the equation given by ideal gas, which follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the sulfur dioxide = 2.00 atm
V = Volume of the sulfur dioxide = 3.50 L
T = Temperature of the mixture = [tex]100^oC=[100+273]K=373K[/tex]
R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]
n = number of moles of sulfur dioxide = ?
Putting values in above equation, we get:
[tex]2.00atm\times 3.50L=n_{SO_2}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 373K\\\\n_{SO_2}=\frac{2.00\times 3.50}{0.0821\times 373}=0.228mol[/tex]
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Moles of sulfur dioxide = 0.228 moles
Molar mass of sulfur dioxide = 64 g/mol
Putting values in above equation, we get:
[tex]0.228mol=\frac{\text{Mass of sulfur dioxide}}{64g/mol}\\\\\text{Mass of sulfur dioxide}=(0.228mol\times 64g/mol)=14.6g[/tex]
Hence, the mass of sulfur dioxide is 14.6 grams
