Two identical loudspeakers 2.0 m apart are emitting 1800 Hz sound waves into a room where the speed of sound is 340 m/s.
Is the point 4.0 m directly in front of one of the speakers, perpendicular to the plane of the speakers, a point of maximum constructive interference, perfect destructive interference, or something in between?

Respuesta :

Answer:

a point of destructive interference.

Explanation:

the wavelength of the sound:

λ= v/f

v= velocity of sound =340 m/s

f= frequency of sound wave= 1800 Hz

L_1 = 4 m

then speaker is at the distance of

[tex]L_2 = sqrt(4^2+2^2)[/tex]

= 2√5 m  

ΔL = L_2-L_1

x = ΔL/λ

Now, if this result is an integer, the waves will add up  at the point. If it is nearly an integer + 0.5, the waves will have a destructive interference at the point. If it is neither of them , then  point is "something in between".

[tex]x= \frac{2\sqrt{5}-4 }{\frac{340}{1800} } =2.4995[/tex]

which is  close to 2.5, an integer + 0.5. So it's a point of destructive interference.

The result is within an integer value of +0.5, thus its a point of destructive interference.

The given parameters;

  • distance between the speakers, d = 2.0 m
  • frequency, f = 1800 Hz
  • speed of the sound, v = 340 m/s
  • distance below the speakers, c = 4 m

The resultant distance between the speakers is calculated as follows;

[tex]L = \sqrt{2^2 + 4^2} \\\\L = 4.47 \ m[/tex]

The wavelength of the sound wave is calculated as;

[tex]v = f\lambda\\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{340}{1800} \\\\\lambda = 0.188 \ m[/tex]

Now, determine if the point is constructive interference, perfect destructive interference, or something in between?

[tex]x = \frac{\Delta L}{\lambda} \\\\x = \frac{4.47 - 4}{0.188} \\\\x = 2.5[/tex]

The result is within an integer value of +0.5, thus its a point of destructive interference.

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