Respuesta :
Answer:
a point of destructive interference.
Explanation:
the wavelength of the sound:
λ= v/f
v= velocity of sound =340 m/s
f= frequency of sound wave= 1800 Hz
L_1 = 4 m
then speaker is at the distance of
[tex]L_2 = sqrt(4^2+2^2)[/tex]
= 2√5 m
ΔL = L_2-L_1
x = ΔL/λ
Now, if this result is an integer, the waves will add up at the point. If it is nearly an integer + 0.5, the waves will have a destructive interference at the point. If it is neither of them , then point is "something in between".
[tex]x= \frac{2\sqrt{5}-4 }{\frac{340}{1800} } =2.4995[/tex]
which is close to 2.5, an integer + 0.5. So it's a point of destructive interference.
The result is within an integer value of +0.5, thus its a point of destructive interference.
The given parameters;
- distance between the speakers, d = 2.0 m
- frequency, f = 1800 Hz
- speed of the sound, v = 340 m/s
- distance below the speakers, c = 4 m
The resultant distance between the speakers is calculated as follows;
[tex]L = \sqrt{2^2 + 4^2} \\\\L = 4.47 \ m[/tex]
The wavelength of the sound wave is calculated as;
[tex]v = f\lambda\\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{340}{1800} \\\\\lambda = 0.188 \ m[/tex]
Now, determine if the point is constructive interference, perfect destructive interference, or something in between?
[tex]x = \frac{\Delta L}{\lambda} \\\\x = \frac{4.47 - 4}{0.188} \\\\x = 2.5[/tex]
The result is within an integer value of +0.5, thus its a point of destructive interference.
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