From a sample with n = 32​, the mean number of televisions per household is 4 with a standard deviation of 1 television. Using​Chebychev's Theorem, determine at least how many of the households have between 2 and 6 televisions.At least ____ of the households have between 2 and 6 televisions.

Respuesta :

Answer:

Atleast, 88.9% of the households have between 2 and 6 televisions.                                      

Step-by-step explanation:

We are given the following in he question:

Sample size, n = 32

Mean, μ = 4

Standard Deviation, σ = 1

Chebychev's Theorem:

  • I states that atleast  [tex]1 - \dfrac{1}{k^2}[/tex]  percent of data lies within k standard deviations for a non normal data.
  • For k = 2

[tex]1-\dfrac{1}{2^2} = 0.75[/tex]

Atleast 75% of data lies within 2 standard deviation of mean.

  • For k = 3

[tex]1-\dfrac{1}{3^2} = 0.889[/tex]

Atleast 88.9% of data lies within 3 standard deviation of mean.

[tex]2 = \mu - 2\sigma = 4 - 2(1)\\6 = \mu + 2\sigma = 4 +2(1)[/tex]

Thus, we have to find data within two standard deviations.

Atleast, 88.9% of the households have between 2 and 6 televisions.