Answer:
238 Degree
Explanation:
Data given
F1=(3.3,-0.5) and F2=(-3.8,-0.3).
To determine the angle F1+F2 makes with the positive x-axis, we need to determine the magnitude of the force F1+F2.
Since force is a vector quantity, we add the vectors component by component
[tex]F_{1}+F_{2}=<3.3,-0.5> +<-3.8,-0.3>\\F_{1}+F_{2}=<3.3+(-3.8), -0.5+(-0.3)>\\ F_{1}+F_{2}=<-0.5,-0.8>\\F_{1}+F_{2}=(-0.5,-0.8)[/tex]
To determine the angle, we use
[tex]F=(x,y)\\\alpha=arctan(\frac{y}{x} )\\Hence for \\F_{1}+F_{2}=(-0.5,-0.8)\\\alpha=arctan(\frac{-0.8}{-0.5} )\\\alpha=58^{0}[/tex]
Since the component of the force F1+F2 is a negative y and negative x which are located in the 3rd quadrant, the angle can be calculated as
∝=58+180=238 degree
Hence The angle is measured counterclockwise from the positive x-axis and must be in the range from 0 to 360 degrees is 238 Degree
The angle measured counterclockwise from the positive x-axis is θ = 57.99°
Here we know that:
First, we need to add the forces, we will get:
F1 + F2 = (3.3, -0.5) + (-3.8, -0.3) = (3.3 - 3.8, -0.5 - 0.3))
F1 + F2 = (-0.5, -0.8)
Now, the angle measured counterclockwise from the positive x-axis of a vector
(a, b) is given by:
θ = Atan(b/a).
Where Atan(x) is the inverse tangent function.
So in this case the angle will be:
θ = Atan(-0.8/-0.5) = 57.99°
If you want to learn more about vectors, you can read:
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