Respuesta :
Kate and Will meet at 1 : 09 pm
Solution:
The distance between Quebec City and New York City is 520 miles.
At the point where Kate and Will meet, they would have traveled 520 miles.
Let "t" represent the time it takes Kate to travel a certain distance before they met.
[tex]Distance = speed \times time[/tex]
If Kate drives at 55 mph, the distance covered would be
[tex]Distance = 55 \times t = 55t[/tex]
If Will drives at 75 miles per hour, then the distance covered will be
[tex]Distance = 75 \times t = 75t[/tex]
Since the total distance covered is 520 miles
Which means,
[tex]55t + 75t = 520\\\\130t = 520\\\\t = \frac{520}{130}\\\\t = 4[/tex]
Given that in question,
If Kate leaves Quebec and will leaves New York at 9:09 a.m
4 hours after 9: 09 am, Kate and Will will meet
9: 09 am + 4 hours = 1: 09 pm
Thus they would meet at 1 : 09 pm
