Sydney started biking to the bookstore traveling 9 mph, after some time the bike got a flat so Sydney walked the rest of the way, traveling 7 mph. If the total trip to the bookstore took 7 hours and it was 57 miles away, how long did Sydney travel at each speed?

Respuesta :

Answer:

By bike= 4 hours

By walk= 3 hours

Step-by-step explanation:

Given: Sydney travel by bike at 9 mph

           Sydney travel by walk at 7 mph.

           Total trip time= 7 hours

           Distance to bookstore= 57 miles.

Lets assume the time spent travelling by bike be "x".

∴ Time spent travelling by walk is [tex](7-x)[/tex]

Now, lets find the distance travelled on bike and by walk.

we know, [tex]Distance= speed\times time[/tex]

∴ Distance by bike= [tex]9\times x= 9x[/tex]

   Distance by walk= [tex]7\times (7-x)[/tex]

Using distributive property of multiplication.

∴ Distance by walk= [tex]49-7x[/tex]

Next, forming an equation for total distance travelled to find x.

⇒ [tex]9x+ (49-7x)= 57\ miles[/tex]

Opening parenthesis

⇒ [tex]9x+49-7x= 57[/tex]

⇒[tex]2x+49= 57[/tex]

Subtracting both side by 49

⇒[tex]2x= 8[/tex]

dividing both side by 2

⇒[tex]x= \frac{8}{2}[/tex]

∴[tex]x= 4\ hours[/tex]

Hence, time spent travelling on bike is 4 hours.

Subtituting the value x to find the time spent travelling by walk.

Times spent travelling by walk= [tex]7-4= 3\ hours[/tex]

hence, time spent travelling by walk= 3 hours