Answer:
933.804423995 m/s²
Explanation:
[tex]q_1[/tex] = Charge on particle 1 = 67 µC
[tex]q_2[/tex] = Charge on particle 2 = -25 µC
r = Distance between the particles = 47 cm
k = Coulomb constant = [tex]8.99\times 10^{9}\ Nm^2/C^2[/tex]
m = Mass of particle = 73 g
Electric force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^{9}\times -25\times 10^{-6}\times 67\times 10^{-6}}{0.47^2}\\\Rightarrow F=-68.1677229516\ N[/tex]
The magnitude of force is 68.1677229516 N
Acceleration is given by
[tex]a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{68.1677229516}{0.073}\\\Rightarrow a=933.804423995\ m/s^2[/tex]
The acceleration is 933.804423995 m/s²
