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According to Guinness World Records, the longest home run ever measured was hit by Roy "Dizzy" Carlyle in a minor league game. The ball traveled 188 m (618 ft) before landing on the ground outside the ballpark. (a) If the ball’s initial velocity was in a direction 45o above the horizontal, what did the initial speed of the ball need to be to produce such a home run if the ball was hit at a point 0.9 m (3.0 ft) above ground level? Ignore air resistance, and assume that the ground was perfectly flat. (b) How far would the ball be above a fence 3.0 m (10 ft) high if the fence was 116 m (380 ft) from home plate?

Respuesta :

Hashirriaz830

Answer:

a) 42.9 m/s

b) 41.6m

Explanation:

a)         [tex]V_{0x}=V_{0y}=\frac{v}{\sqrt{2} }[/tex]

           [tex]y(t)=0.3+\frac{v}{\sqrt{2} }t -4.9t^{2} \\188=\frac{vt}{\sqrt{2}} \\[/tex]

solving the eq we get

              v=42.9 m/s

b) here,

              [tex]t=\frac{116\sqrt{2} }{42.9}[/tex]

when put in y(t) it gives y=44.6 m so result is

             h=44.6-3= 41.6m

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