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A mother is three times as old as her son, and in 11 years she will be just twice his age. Find their present ages

Respuesta :

Answer:The kid is 11 and the mother is 33

Step-by-step explanation:

do the math

Step-by-step explanation:

Let the present age of son be x years

Therefore, mother's age = 3x years

11 years after:

Son's age = (x + 11) years

Mother's age = (3x + 11) years

According to the given condition:

3x + 11 = 2 (x + 11)

[tex] \therefore \: 3x + 11 = 2x + 22 \\ \therefore \: 3x - 2x = 22 - 11 \\ \therefore \: x = 11 \\ \implies \: 3x = 3 \times 11 = 33 \\ thus \\ Present \: age \: of \: mother = 33 \: years \\ Present \: age \: of \: son= 11 \: years \\ [/tex]