Answer: 85.8 g AlCl3
Explanation:
Convert molecules of AlCl3 to moles using the Avogadro's number
Convert moles of AlCl3 to mass using its molar mass.
3.913x10²³ molecules AlCl3 x 1mole AlCl3 / (6.022x10²³ molecules AlCl3) X 132g AlCl3/ 1 mole AlCl3
= 85.8 g AlCl3
