Answer:
Explanation:
Calcium is the element of the group 2 and period 4 which means that the valence electronic configuration is [tex]1s^22s^22p^63s^23p^64s^2[/tex] or [tex][Ar]4s^2[/tex].
Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is [tex]1s^22s^22p^63s^23p^5[/tex] or [tex][Ne]3s^23p^5[/tex].
Thus, calcium losses 2 electrons to 2 atoms of chlorine and these 2 atoms of chlorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.
Thus, the formula of calcium chloride is [tex]CaCl_2[/tex].
Hence, in [tex]CaCl_2[/tex], Calcium exits in [tex]Ca^{2+}[/tex] form which has electronic configuration of [tex]1s^22s^22p^63s^23p^6[/tex] or [tex][Ar][/tex]