Answer:
43.76%
Explanation:
The air density at the sea level ρ_s = 1.25 kg/m^3.
also, air density at the top of the mountain where ρ_t = 0.547 kg/m^3.
taking temp as --50° C and pressure as 1/3 of P_atm.
therefore, t percent is the air density at the summit of Mount Everest relative to the air density at sea level
= [tex]\frac{\rho_t}{\rho_s}\times100[/tex]
=[tex]\frac{0.547}{1.25}\times100[/tex]
=43.76 %
