A 4.0-kg mass is moving with speed 2.0 m/s. A 1.0-kg mass is moving with speed 4.0 m/s. Both objects encounter the same constant braking force, and are brought to rest. Which object travels the greater distance before stopping?

Respuesta :

Answer

given,

mass of object 1 = 4 Kg

Speed of object 1 = 2 m/s

mass of object 2 = 1 Kg

speed of object 2 = 4 m/s

KE of the object 1 = [tex]\dfrac{1}{2}MV^2[/tex]

                             = [tex]\dfrac{1}{2}\times 4 \times 2^2[/tex]

                             = 8 J

KE of the object 2 = [tex]\dfrac{1}{2}MV^2[/tex]

                             = [tex]\dfrac{1}{2}\times 1 \times 4^2[/tex]

                             = 8 J

Kinetic energy of both the object is same hence,Work done by both the object will also be same.

It is given that braking force is same in both cases.

So, distance travel by Both the object will be same.

Both of them cover the same amount of distance.

Given that;

4 kg mass is moving with speed 2.0 m/s

1.0 kg mass is moving with speed 4.0 m/s.

Both objects are brought to a halt by the same steady braking force.

Their momentum will be proportionate to their weight in the opposite direction = 1:4 ratio

Distance before coming to rest

v² - u² =2as

So,

s1/s2 = 16/16

Both of them cover the same amount of distance.

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