Answer
given,
length of tube = 120 cm
a) Open at both ends.
distance between two successive nodes or anti nodes = λ/2
for first possibility = λ/2 = 120
λ =2 x 120 = 240 cm
for second Possibility, distance between two node or antinode acting symmetrically
λ = 120 cm
for three nodes in the tube, distance between them is equal to
[tex]\dfrac{3}{2}\lambda = 120[/tex]
[tex]\lambda = 80 cm[/tex]
b) Open at one end
First possibility, The distance between one node or anti node
[tex]\dfrac{\lambda}{4} = 120[/tex]
λ = 480 cm
Second Possibility, distance between two node or anti node is equal to
[tex]\dfrac{3}{4}\lambda = 120[/tex]
λ = 160 cm
Third possibility, distance between three nodes and three anti nodes is equal to
[tex]\dfrac{5}{4}\lambda = 120[/tex]
λ = 100 cm