Answer:
Probability that a 5-card draw hand contains the ace of hearts = 0.0962
Explanation:
a) The selection of 5cards from a deck of 52cards = The knowledge of combination comes in
= nCr = n!/(n-r)!r!
= 52C5 = 52!/(52-5)!5!
= 2598960, hence there are 2598960 ways of selecting 5cards from a deck of 52cards
b) There are 1 ace of heart in a deck of cards, therefore, the number of ways of choosing 1 ace of heart and 4 other cards = nCr
= 1C1 X 51C4
= 1 X 51!/(51-4)!4!
= 249900
c) To find the probability that the 5 cards drawn contain an ace of hearts
= P( 5 cards drawn contain an ace of hearts) = number of favorable outcomes/ total number of outcomes
= 249900/ 2598960
= 0.0962
