contestada

A force of 6 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching it from its natural length to 11 in. beyond its natural length?

Respuesta :

princessesther2011

Answer:

Work done is 1.02J

Step-by-step explanation:

Work (W) done in stretching a spring = 1/2Fe

F (force) = 6 lb = 6×4.4482N = 26.6892N

e (extension) = 11in - 8in = 3in = 3×0.0254m = 0.0762m

W = 1/2 × 26.6892 × 0.0762 = 1.02J

Otras preguntas