Answer:
Step-by-step explanation:
Given that you choose at random a real number X from the interval [2, 10].
a) Since this is a contnuous interval with all number in between equally likely
E = probability for choosing a real number is U(2,10)
pdf of E is [tex]\frac{1}{8}[/tex]
b) P(X>5) = [tex]\int\limits^10_5 {1/8} \, dx = \frac{5}{8}[/tex]
[tex]P(5<x<7) = \frac{2}{8} =\frac{1}{4}[/tex]
For
[tex]x^2-12x+35 >0\\(x-5)(x-7)>0\\x<5 or x >7[/tex]
P(X<5 or x>7) = 1-P(5<x<7)
= [tex]\frac{3}{4}[/tex]