Answer: Let number of red balls = n
number of black balls = m
number of red and black balls = n + m
Step-by-step explanation:
a) number of n balls chosen, X = n/n+m
b) number of n balls chosen without replacement, E(X) = n/n+m*{n/n+m-1}
∴ E(X) = n²/n²+2nm+m²+n-m