Respuesta :
Answer:
The answer is 12.35
Explanation:
From the question we are given that the concentration of [tex]H^{+}[/tex] is [tex]8.1 * 18^{-6}M[/tex]
Generally The rate equation is given as
[tex]K_{w} = [H^{+} ][OH^{-} ][/tex]
and [tex]K_{w}[/tex] the rate constant has a value [tex]1 * 10^{-14}[/tex]
Substituting and making [[tex]OH^{-}[/tex]] the subject we have
[tex][OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}[/tex]
[tex][OH ^ {-}] = 1.235 * 10^{-9}M[/tex]
Multiply the value by [tex]10^{10}[/tex] as instructed from the question we have
Answer = [tex]1.235 * 10 ^{-9} * 10^{10} = 12.35[/tex]
Hence the answer in 2 decimal places is 12.35
The concentration of OH¯ in the solution multiplied by 10¹⁰ is 12.35
Data obtained from the question:
- Concentration of Hydrogen ion [H⁺] = 8.1×10¯⁶ M
- Concentration of Hydroxide ion [OH¯] =?
How to determine [OH¯]
The concentration of hydroxide ion [OH¯] can be obtained as follow:
K = [H⁺][OH¯]
Equilibrium constant (K) = 1×10¯¹⁴
1×10¯¹⁴ = 8.1×10¯⁶ × [OH¯]
Divide both side by 8.1×10¯⁶
[OH¯] = 1×10¯¹⁴ / 8.1×10¯⁶
[OH¯] = 1.235×10¯⁹
Multiply by 10¹⁰
[OH¯] = 1.235×10¯⁹ × 10¹⁰
[OH¯] = 12.35
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