Calculate the concentration of OH-in a solution that has a concentration of H+ = 8.1 x 10^−6 M at 25°C. Multiply the answer you get by 1010 and enter that into the field to 2 decimal places.

Respuesta :

Answer:

The answer is 12.35

Explanation:

From the question we are given that the concentration of [tex]H^{+}[/tex] is [tex]8.1 * 18^{-6}M[/tex]

 Generally The rate equation is given as

                                                           [tex]K_{w} = [H^{+} ][OH^{-} ][/tex]

and [tex]K_{w}[/tex] the rate constant has a value [tex]1 * 10^{-14}[/tex]

     Substituting and making [[tex]OH^{-}[/tex]] the subject we have

                                                 [tex][OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}[/tex]

                                                  [tex][OH ^ {-}] = 1.235 * 10^{-9}M[/tex]

                            Multiply the value by [tex]10^{10}[/tex] as instructed from the question we have  

                       Answer =   [tex]1.235 * 10 ^{-9} * 10^{10} = 12.35[/tex]

Hence the answer in 2 decimal places is 12.35

The concentration of OH¯ in the solution multiplied by 10¹⁰ is 12.35

Data obtained from the question:

  • Concentration of Hydrogen ion [H⁺] = 8.1×10¯⁶ M
  • Concentration of Hydroxide ion [OH¯] =?

How to determine [OH¯]

The concentration of hydroxide ion [OH¯] can be obtained as follow:

K = [H⁺][OH¯]

Equilibrium constant (K) = 1×10¯¹⁴

1×10¯¹⁴ = 8.1×10¯⁶ × [OH¯]

Divide both side by 8.1×10¯⁶

[OH¯] = 1×10¯¹⁴ / 8.1×10¯⁶

[OH¯] = 1.235×10¯⁹

Multiply by 10¹⁰

[OH¯] = 1.235×10¯⁹ × 10¹⁰

[OH¯] = 12.35

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