Answer:
[tex]{P_2}=146.53\ kPa[/tex]
Explanation:
Volume ,V = 3 L
Initial temperature ,T₁ = 273 K
Initial pressure ,P₁ = 105 kPa
Final temperature ,T₂ = 381 K
Lets take final pressure =P₂
We know that ,If the volume of the gas is constant ,then we can say that
[tex]\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}[/tex]
[tex]{P_2}=P_1\times \dfrac{T_2}{T_1}[/tex]
Now by putting the values in the above equation we get
[tex]{P_2}=105\times \dfrac{381}{273}\ kPa[/tex]
[tex]{P_2}=146.53\ kPa[/tex]
Therefore the final pressure will be 146.53 kPa.
