Answer:
t = 4.62 sec
Explanation:
For every first order reaction the rate constant K is given as
[tex]k =(\frac{2.303}{t} )log\frac{[A_{o} ]}{[A]}[/tex]
[tex][A_{o} ] = initial concentration = 0.52\frac{mol}{L}[/tex]
[tex][A] =final concentration = 0.358 \frac{mol}{L}[/tex]
[tex]K = 0.0808 sec^{-1}[/tex]
[tex]t = (\frac{2.303}{K} ) log (\frac{[A_{o} ]}{[A]} )[/tex]
[tex]= (\frac{2.303}{0.0808} )log (\frac{0.52}{0.358} )[/tex]
t = 4.62 sec
