Answer:
[tex]E' = \frac{1}{8} E[/tex]
Explanation:
Given data:
first case
Distance of electric field from center of sphere is r_1 <R
Electric field at r_1< R
[tex]E = \frac{kQr_1}{R^3}[/tex]
second case
Distance of electric field from centre of sphere is r_1 < 2R
Electric field at r_1< 2R
[tex]E' = \frac{kQr_1}{8R^3}[/tex]
so, we have
[tex]E' = \frac{1}{8} E[/tex]