Answer:
Step-by-step explanation:
If the equation of the of the hyperbola is , then the eccentricity, and the directrices are and the foci are (± ae,0).
Now, given that ae = 4 and ......... (1)
So,
⇒ a² = 8
⇒ a = 2√2 units.
Now, from equation (1) we get, ae = 4
⇒ e = √2 as a = 2√2
Now,
⇒
⇒ b² = 8
Hence, the equation of the hyperbola is
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