The mass of aluminium hydroxide is 81.12 g.
Explanation:
The chemical equation for the decomposition of Aluminium hydroxide follows:
2 Al(OH)3 ------> Al2O3 + 3H2O
At STP:
22.4 L of volume is occupied by 1 mole of a gas.
So, 35 L of the volume will be occupied by = (1 / 22.4) [tex]\times[/tex] 35 = 1.56 mol
By Stoichiometry of the reaction:
3 moles of water is produced by 2 moles of Aluminium hydroxide
So, 1.56 moles of water is produced by = (2 /3) [tex]\times[/tex] 1.56 = 1.04 mol.
To calculate the mass of Aluminium hydroxide, we use the equation:
Number of moles = given mass / molar mass
Number of moles of Aluminium hydroxide = 1.04 mol
The Molar mass of Aluminium hydroxide = 78 g/mol
Putting values in above equation, we get:
1.04 mol = mass of Aluminium hydroxide / 78
The mass of Aluminium hydroxide needed is 81.12 grams.
