Solve this system of equations story problem by any method of your choice. Describe what the number solutions mean in terms of the real life application.
Jasmine and Stephanie are selling pies for a school fundraiser. Customers can buy cherry pies
and blackberry pies. Jasmine sold 12 cherry pies and 4 blackberry pies for a total of $136.
Stephanie sold 8 cherry pies and 1 blackberry pie for a total of $64. What is the cost each of one
cherry pie and one blackberry pie?

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jitushashi56 jitushashi56 · Answer 1 · 2020-02-13T10:18:35+01:00

Answer:

Cost of each cherry pie = $6

Cost of each blackberry pie = $16

Step-by-step explanation:

Let x be the cherry pies and y be the blackberry pie.

Solution:

From the above statement Jasmine sold 12 cherry pies and 4 blackberry pies for a total of $136.

So, we write the first equation as.

[tex]12x+4y = 136 ------(1)[/tex]

And Stephanie sold 8 cherry pies and 1 blackberry pie for a total of $64.

So, we write the second equation as.

[tex]8x+y = 64 --------(2)[/tex]

First we solve equation 2 for y.

[tex]y = 64-8x[/tex] ------------------------(3)

Substitute [tex]y = 64-8x[/tex] in equation 1.

[tex]12x+4(64-8x) = 136[/tex]

[tex]12x+256-32x=136[/tex]

[tex]12x-32x=136-256[/tex]

[tex]-20x=-120[/tex]

[tex]x=\frac{120}{20}[/tex]

x = 6

Substitute x = 6 in equation 3.

[tex]y = 64-8(6)[/tex]

[tex]y=64-48[/tex]

y = 16

Therefore, cost of each cherry pie = $6 and cost of each blackberry pie = $16