1. Type an equation in the equation editor that uses 2 fractions with parentheses around one of them. Example: [tex]\frac{2}{3}[/tex] + (- [tex]\frac{1}{2}[/tex]) = [tex]\frac{4}{6} - \frac{3}{6} = \frac{1}{6}[/tex]

2. Type an expression that has two terms with exponents, and one with a square root. Example: [tex]2^{3}[/tex] + [tex]9^{2}[/tex] + [tex]\sqrt{16}[/tex]

3. Type a compound inequality similar to the one below, but with different numbers. It should be set up the same, with all the symbols in the same places. [tex](\frac{3}{5} )^{2}[/tex] · [tex]^{3} \sqrt{10} \leq x^{3} - 2x + 5 \leq \sqrt{\frac{1}{3}[/tex]

i) [tex]\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex] [tex]\Rightarrow[/tex] \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)[tex]4^{3} + 8^{2} + \sqrt{9}[/tex] [tex]\Rightarrow[/tex] 4^{3} + 8^{2} + \sqrt{9}

iii) [tex](\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}[/tex] (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

Step-by-step explanation:

i) [tex]\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex] [tex]\Rightarrow[/tex] \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)[tex]4^{3} + 8^{2} + \sqrt{9}[/tex] [tex]\Rightarrow[/tex] 4^{3} + 8^{2} + \sqrt{9}

iii) [tex](\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}[/tex] (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}