Find the probability of having 2, 3, or 4 successes in five trials of a binomial experiment in which the probability of success is 40%.
Round to the nearest tenth of a percent
[?]%

Respuesta :

Answer:

P=65%

Step-by-step explanation:

Binomial Distribution

The probability will be calculated by using the Binomial Distribution with n independent events each with a probability of success equal to p with k successes.  

The PMF (Probability Mass Function) is

[tex]\displaystyle F(k,n,p)=\binom{n}{k}p^kq^{n-k}[/tex]

Where  

[tex]q = 1-p[/tex]

We have n=5trials with k=2, 3, or 4 successes. Each individual experience has [tex]p = 0.4 , q = 0.6[/tex]

First, we compute for k=2

[tex]\displaystyle F(2,5,0.4)=\binom{5}{2}0.4^20.6^{3}=0.3456[/tex]

Now for k=3

[tex]\displaystyle F(3,5,0.4)=\binom{5}{3}0.4^30.6^{2}=0.2304[/tex]

Finally for k=4

[tex]\displaystyle F(4,5,0.4)=\binom{5}{4}0.4^40.6^{1}=0.0768[/tex]

The required probability is  

[tex]P=0.3456+0.2304+0.0768=0.6528[/tex]

P=65%