Step-by-step explanation:
[tex]50 \geqslant 15x \\ \\ \implies \: \frac{50}{15} \geqslant x\\ \\ \implies \: \frac{10}{3} \geqslant x \\ \\ \therefore \: x \leqslant \frac{10}{3} \\ thus \: \{x \: | \: x \leqslant \frac{10}{3} \} \: is \: the \: correct \: \\ solution \: set.[/tex]
