Units of J: [tex][\frac{m}{s^3}][/tex]
Step-by-step explanation:
The quantity defined in this problem is
[tex]J=\frac{a}{t}[/tex]
where:
a is the acceleration
t is the time
The units of the two quantities are:
a (acceleration) is measured in metres per second squared, [tex][\frac{m}{s^2}][/tex]
t (time) is measured in seconds, [tex][s][/tex]
Therefore, the quantity J is measured in:
[tex][J]=\frac{[\frac{m}{s^2}]}{[s^3]}=[\frac{m}{s^3}][/tex]
which is option B.
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