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The tomato is dropped. What is the velocity, vvv, of the tomato when it hits the ground? Assume 93.8 %% of the work done in Part A is transferred to kinetic energy, EEE, by the time the tomato hits the ground.

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Answer:

the velocity of the tomato will be  v  = u + gt

kinetic energy = 9.64 h

Explanation:

  • The tomato is dropped from a height, so before it lands on the ground, it possesses potential energy. This is the energy relative to its height from the ground.

At that time, let the initial speed be u.

The acceleration due to gravity be g

The final velocity will be given as v = u + at

but a = g = 9.81 m/s² [acceleration due to gravity]

so the final velocity will be given as v = u + at

Let the potential energy be Ep

Before landing the ground, 93.8 % of the potential energy will be converted to kinetic energy. Therefore, the calculation will be as follows:

Ep = mgh

Kinetic energy Ek = 1/2mv²

But, Ek = 0.938 Ep

            = 0.983 × gh

            = 9.64 h

where h is the height of the object from the ground.

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