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Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2(g) ⇌ COCl2(g) If 0.430 mol of each reactant is placed in a 0.500−L flask at 600 K, what are the concentrations of all three substances at equilibrium (Kc = 4.95 at this temperature)?

Respuesta :

Answer: Concentration of [tex]CO[/tex] = 0.328 M

Concentration of [tex]Cl_2[/tex] = 0.328 M

Concentration of [tex]COCl_2[/tex] = 0.532 M

Explanation:

Moles of  [tex]CO[/tex] and [tex]Cl_2[/tex] = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of [tex]CO[/tex] and [tex]Cl_2[/tex]  =[tex]\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M[/tex]

The given balanced equilibrium reaction is,

                            [tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]

Initial conc.          0.860M     0.860M           0

At eqm. conc.    (0.860-x) M  (0.860-x) M     (x) M

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[COCl_2]}{[CO][Cl_2]}[/tex]

Now put all the given values in this expression, we get :

[tex]4.95=\frac{x}{(0.860-x)^2}[/tex]

By solving the term 'x', we get :

x =  0.532 M

Thus, the concentrations of [tex]CO,Cl_2\text{ and }COCl_2[/tex] at equilibrium are :

Concentration of [tex]CO[/tex] = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of [tex]Cl_2[/tex] =  (0.860-x) M  =  (0.860-0.532) M = 0.328 M

Concentration of [tex]COCl_2[/tex] = x M = 0.532 M