Answer:
2.57 cm or 2.57×10⁻² m
Explanation:
From coulomb's law,
F = kqq'/r²................. Equation 1
Where F = force between the charges, q and q' = The first and second charge respectively, k = constant of proportionality, r = distance between the charges.
Making r the subject of equation 1
r = √(kqq'/F)................ Equation 2
Given: F = 0.67 N, q = 1.2 μC = 1.2×10⁻⁶ C, q' = 4.1×10⁻⁶ C
Constant: k = 9×10⁹ Nm²/C².
Substitute into equation 2
r = √( 1.2×10⁻⁶×4.1×10⁻⁶×9×10⁹/0.67)
r = √(66.09×10⁻³)
r = √(6.609×10⁻⁴)
r = 2.57×10⁻² m
r = 2.57 cm or 2.57×10⁻² m
Hence the distance between the charge = 2.57 cm or 2.57×10⁻² m
