The percent volume change associated with this reaction is 97.66 %.
Allotropic transformation is a change in the physical form of material.
Given, rBCC = 0.12584 nm
rFCC = 0.12894
Step 1: For a rBCC (α phase) structure, the unit cell length and atomic radius is equal
[tex]a_B_C_C=\dfrac{4\times 0.12584}{\sqrt{3} }=0.2906\; nm[/tex]
Now, for rFCC,
[tex]a_B_C_C=\dfrac{(4R_F_C_C)}{\sqrt{2} }[/tex]
[tex]a_B_C_C=\dfrac{4\times 0.12894 }{\sqrt{3} }= 0.3647\; nm[/tex]
Step 2: The percent volume change is:
[tex]\bigtriangleup V= \dfrac{(V_f-V_i)}{V_initial} \times100[/tex]
[tex]\bigtriangleup V & =\dfrac{( V_F_C_C3) -(V_B_C_C3)}{〖V_B_C_C3 } \times100 = \dfrac{0.3647}{0.2906} \times100 = 97.66 \%[/tex]
Thus, the percent volume change is 97.66 %
Learn more allotropic transformation, here:
https://brainly.com/question/2256682
