Respuesta :
Answer:
A. Yes, the calculated density in agreement with the tabulated value.
B. 19.28 mL of volume of cyclohexane should be used.
C. 742.20 is the mass of the sphere of lead.
Explanation:
A.
Volume of the liquid = V = 25.0 mL
Mass of the liquid = m = 21.95 g
Density of the liquid = d
[tex]d=\frac{m}{V}[/tex]
[tex]=\frac{21.95 g}{25.0 mL}=0.878 g/mL[/tex]
Density mentioned in the report book = d' = 0.878 g/mL
d' = d = 0.878 g/mL
Yes, the calculated density in agreement with the tabulated value.
B.
Volume of the liquid cyclohexane= V = ?
Mass of the liquid cyclohexane= m = 15.0 g
Density of the liquid cyclohexane = d = 0.7781 g/mL
[tex]d=\frac{m}{V}[/tex]
[tex]V=\frac{15.0 g}{0.7781 g/mL}=19.28 mL[/tex]
19.28 mL of volume of cyclohexane should be used.
C.
Diameter of the ball = d = 5.0 cm
Radius of the ball = r = 0.5 × d = 2.5 cm
Volume of sphere ,V= [tex]\frac{4}{3}\pi r^3[/tex]
[tex]V = \frac{4}{3}\times 3.14\times (0.25 cm)^3=65.45 cm^3[/tex]
Volume of the spherical lead ball = V
Mass of the spherical lead ball= m = ?
Density of the spherical lead ball = d = [tex]11.34 g/cm^3[/tex]
[tex]d=\frac{m}{V}[/tex]
[tex]m=d\times V=11.34 g/cm^3\times 65.45 cm^3=742.20 g[/tex]
742.20 is the mass of the sphere of lead.
