Answer:
n≅376
So sample size is 376.
Step-by-step explanation:
The formula we are going to use is:
[tex]n=pq(\frac{z_{\alpha/2}}{E})^{2}[/tex]
where:
n is the sample size
p is the probability of favor
q is the probability of not in favor
E is the Margin of error
z is the distribution
α=1-0.98=0.02
α/2=0.01
From cumulative standard Normal Distribution
[tex]z_{\alpha/2}=2.326[/tex]
p is taken 0.5 for least biased estimate, q=1-p=0.5
[tex]n=0.5*0.5(\frac{2.326}{0.06})^{2}\\n=375.71[/tex]
n≅376
So sample size is 376