Answer:
probability = 0.05761
Explanation:
given data
P(X) = 30% = 0.30
P(Y | X) = 15% = 0.15
P( Y' | X') = 8% = 0.08
here X is package is delivered
and Y is weight 2 lbs or more
solution
here we can say that P(X and Y) is express as
P(X and Y) = P(Y|X) × P(X) .............1
put here value and we get
P(X and Y) = 0.15 × 0.30
P(X and Y) = 0.045
so probability of package is delivered of weighs 2 lbs or more P (Y) is
P (Y) = P(Y|X) × P(X) + P(Y|X') × P(X') ............2
put here value we get
P (Y) = 0.15 × 0.30 + 0.8 × 0.92
P (Y) = 0.781
so required probability is = [tex]\frac{P(X\ and\ Y) }{P(Y)}[/tex]
probability = [tex]\frac{0.045}{0.781}[/tex]
probability = 0.05761
