contestada

an electron aquires 3.45 e-16j of kinetic energy when it is accelerated by an electric field from plate a to b in a computer monitor what is the potential difference between the plates and which plate has the higher potential?

Respuesta :

Answer:

Potential difference will be equal to 2156.25 volt

Explanation:

We have given kinetic energy of electron [tex]KE=3.45\times 10^{-16}J[/tex]

Charge on electron [tex]e=1.6\times 10^{-19}C[/tex]

Let the potential difference is V

So energy electron will be equal to [tex]E=qV[/tex], here q is charge on electron and V is potential difference

This energy will be equal to kinetic energy of the electron

So [tex]1.6\times 10^{-19}\times V=3.45\times 10^{-16}[/tex]

V = 2156.25 volt

So potential difference will be equal to 2156.25 volt

Otras preguntas