Answer:
The vertex of the function is at point (-4,-1).
Step-by-step explanation:
Given function:
[tex]f(x)=(x+4)^2-1[/tex]
Solution:
The vertex form of a function is given by:
[tex]f(x)=a(x-h)^2+k[/tex]
where [tex](h,k)[/tex] is the vertex of the function. At this point the function has the maximum or minimum value.
Writing the given function in the vertex form.
[tex]f(x)=(x-(-4))^2+(-1)[/tex]
On comparing the above function with the standard form we find that:
[tex]a=1\\h=-4\\k=-1[/tex]
Thus, the vertex of the function is at point (-4,-1)
