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My sling shot shoots pellets at 50m/s. Find two angles of elevation that can be used to hit a target 65m away. (Assume air resistance is negligible. Assume the gravitational constant ????=10m/s2 for this problem.)

Respuesta :

Answer:

Explanation:

Given

velocity of launch [tex]u=50\ m/s[/tex]

Target is [tex]R=65\m\ away[/tex]

Suppose [tex]\theta [/tex] is the launch angle

We know Range of Projectile is

[tex]R=\frac{u^2\sin 2\theta }{g}[/tex]

[tex]65=\frac{50^2\times \sin 2\theta }{9.8}[/tex]

[tex]\sin 2\theta =0.254[/tex]

because [tex]\sin \theta =\sin (180-\theta )[/tex]

so either [tex]2\theta =14.71[/tex]

[tex]\theta =7.35^{\circ}[/tex]

or [tex]180-2\theta =14.71[/tex]

[tex]\theta =82.64^{\circ}[/tex]

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