To see if the point is on the line, plug in one of the point values to see if it equals out.
y = 4x - 2 I will plug in 1 for x to see if y does = 3
y = 4(1) - 2
y = 4 - 2
y = 2 so (1, 2)
Dinesh is not correct because the point on the line when x = 1 is (1, 2) not (1, 3)