Answer:
Explanation:
Given
mass of first child [tex]m_1=20\ kg[/tex]
mass of second child [tex]m_2=30\ kg[/tex]
Distance between two children is [tex]d=3\ m[/tex]
Suppose light weight child is placed at a distance of x m from Pivot point
therefore
Torque due to heavy child [tex]T_1=m_2g\times (3-x)[/tex]
Torque due to small child [tex]T_2=m_1g\times x[/tex]
Net Torque about Pivot must be zero
Therefore [tex]T_1=T_2[/tex]
[tex]30\times g\times (3-x)=20\times g\times x[/tex]
[tex]9-3x=2x[/tex]
[tex]9=5x[/tex]
[tex]x=\frac{9}{5}[/tex]
[tex]x=1.8\ m[/tex]
