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Consider the chemical reaction described by the following equation.
HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
ΔH = −58 kJ
What would be the enthalpy, in kilojoules, for the reaction
2NaCl(aq) + 2H2O(l) → 2HCl(aq) + 2NaOH(aq)
ΔH = ?

Respuesta :

ajeigbeibraheem

Answer:

ΔH = + 116 kJ

Explanation:

The equation for the reaction is given as;

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)                    ΔH = - 58 kJ

If we multiply the above equation all through with (2); we have:

2 × (HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)             ΔH = - 58 kJ)

2HCl(aq) + 2NaOH(aq)  → 2NaCl(aq) + 2H2O(l)          ΔH = - 116 kJ

If we tend to reverse the above equation; we have

2NaCl(aq) + 2H2O(l)  →  2HCl(aq) + 2NaOH(aq)         ΔH = + 116 kJ

∴ The reaction is said to be endothermin , as 116 kJ are absorbed.

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