Answer:
vertical load = 10 kN
Modulus of elasticity = 200GPa
Yield stress on the cable = 400 MPa
Safety factor = 2.0
Explanation:
Data
let L = [tex]\sqrt{(1.5)^{2} + (1.5)^{2} }[/tex]
= 3.35 m
substituting 1.5 m for h and 3 m for the tern (a + b)
[tex]\theta[/tex] = tan⁻¹([tex]\frac{1.5}{1.5}[/tex])
= 45⁰
substituting 1.5 for h and 3 m for (a+ b) yields:
[tex]\theta[/tex]₂ = tan⁻¹ ([tex]\frac{1}{3}[/tex])
=25.56⁰
checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.
