Oscilloscopes are found in most science laboratories. Inside, they contain deflecting plates consisting of more-or-less square parallel metal sheets, typically about 2.50 cm on each side and 2.00 mm apart. In many experiments, the maximum potential across these plates is about 30.0 V.

1.For this maximum potential, what is the strength of the electric field between the plates? [V/m]

2.For this maximum potential, what magnitude of acceleration would this field produce on an electron midway between the plates? [m/s^2]

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boffeemadrid boffeemadrid · Answer 1 · 2020-02-07T07:55:45+01:00

Answer:

15000 V/m

[tex]2.634467618\times 10^{15}\ m/s^2[/tex]

Explanation:

V = Voltage = 30 V

d = Separation = 2 mm

q = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]

m = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]

Electric field is given by

[tex]E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{30}{2\times 10^{-3}}\\\Rightarrow E=15000\ V/m[/tex]

The electric field between the plates is 15000 V/m

Acceleration is given by

[tex]a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times 15000}{9.11\times 10^{-31}}\\\Rightarrow a=2.634467618\times 10^{15}\ m/s^2[/tex]

The acceleration is [tex]2.634467618\times 10^{15}\ m/s^2[/tex]