Answer:
127.15 °C
Explanation:
Gay-Lussac's law states that the pressure of a given mass of gas directly proportional to the absolute temperature of the gas at constant volume.
Mathematically,
P₁ / T₁ = P₂ / T₂ -----(1)
Data Given:
Initial Pressure = P₁ = 1 atm (assumed)
Initial Temperature = T₁ = -73°C = 200.15 K
Final Pressure = P₂ = 2 atm (doubled)
Final Temperature = T₂ = ????
Solving equation 1 for T₂,
T₂ = P₂ × T₁ / P₁
Putting these values;
T₂ = 2 atm × 200.15 K / 1 atm
T₂ = 400.3 K
Or,
T₂ = 127.15 °C
Conclusion:
By doubling the pressure results in increase in temperature.
