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A businesswoman is rushing out of a hotel through a revolving door with a force of 80 N applied at the edge of the 3 m wide door. Where is the pivot point and what is the maximum torque?

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Answer:

Explanation:

Given

Force applied [tex]F=80\ N[/tex]

Door is [tex]d=3\ m[/tex] wide

for gate to revolve Properly Pivot Point must be at center i.e. 1.5 from either end

Torque applied is [tex]T=force\times distance[/tex]

Maximum torque

[tex]T_{max}=F\times \frac{d}{2}[/tex]

[tex]T_{max}=80\times \frac{3}{2}[/tex]

[tex]T_{max}=120\ N-m[/tex]

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