Answer:
Step-by-step explanation:
Given that A is a square matrix and A is idempotent
[tex]A^2 = A[/tex]
Consider I-A
i) [tex](I-A)^2 = (I-A).(I-A)\\= I^2 -2A.I+A^2\\= I-2A+A\\=I-A[/tex]
It follows that I-A is also idempotent
ii) Consider the matrix 2A-I
[tex](2A-I).(2A-I)=\\4A^2-4AI+I^2\\= 4A-4A+I\\=I[/tex]
So it follows that 2A-I matrix is its own inverse.